Solve (8^2+6^2-4^2/8

$$\frac{ ( { 8 }^{ 2 } + { 6 }^{ 2 } - { 4 }^{ 2 } }{ 8 }$$

Evaluate

$$\frac{21}{2}=10.5$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$\frac{64+6^{2}-4^{2}}{8}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{64+36-4^{2}}{8}$$

Add 64 and 36 to get 100.

$$\frac{100-4^{2}}{8}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{100-16}{8}$$

Subtract 16 from 100 to get 84.

$$\frac{84}{8}$$

Reduce the fraction \frac{84}{8} to lowest terms by extracting and canceling out 4.

$$\frac{21}{2}$$

Factor

$$\frac{3 \cdot 7}{2} = 10\frac{1}{2} = 10.5$$