Solve (1^3+1)-(1^3+1)/10^-6

$$\frac{ ( { 1 }^{ 3 } +1)-( { 1 }^{ 3 } +1) }{ { 10 }^{ -6 } }$$

Evaluate

$$0$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$\frac{1+1-\left(1^{3}+1\right)}{10^{-6}}$$

Add 1 and 1 to get 2.

$$\frac{2-\left(1^{3}+1\right)}{10^{-6}}$$

Calculate 1 to the power of 3 and get 1.

$$\frac{2-\left(1+1\right)}{10^{-6}}$$

Add 1 and 1 to get 2.

$$\frac{2-2}{10^{-6}}$$

Subtract 2 from 2 to get 0.

$$\frac{0}{10^{-6}}$$

Calculate 10 to the power of -6 and get \frac{1}{1000000}.

$$\frac{0}{\frac{1}{1000000}}$$

Zero divided by any non-zero number gives zero.

$$0$$

Factor

$$0$$