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x^{2}+4x-4=0
Variable x cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by \left(x+2\right)^{2}.
x=\frac{-4±\sqrt{4^{2}-4\left(-4\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 4 for b, and -4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-4±\sqrt{16-4\left(-4\right)}}{2}
Square 4.
x=\frac{-4±\sqrt{16+16}}{2}
Multiply -4 times -4.
x=\frac{-4±\sqrt{32}}{2}
Add 16 to 16.
x=\frac{-4±4\sqrt{2}}{2}
Take the square root of 32.
x=\frac{4\sqrt{2}-4}{2}
Now solve the equation x=\frac{-4±4\sqrt{2}}{2} when ± is plus. Add -4 to 4\sqrt{2}.
x=2\sqrt{2}-2
Divide -4+4\sqrt{2} by 2.
x=\frac{-4\sqrt{2}-4}{2}
Now solve the equation x=\frac{-4±4\sqrt{2}}{2} when ± is minus. Subtract 4\sqrt{2} from -4.
x=-2\sqrt{2}-2
Divide -4-4\sqrt{2} by 2.
x=2\sqrt{2}-2 x=-2\sqrt{2}-2
The equation is now solved.
x^{2}+4x-4=0
Variable x cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by \left(x+2\right)^{2}.
x^{2}+4x=4
Add 4 to both sides. Anything plus zero gives itself.
x^{2}+4x+2^{2}=4+2^{2}
Divide 4, the coefficient of the x term, by 2 to get 2. Then add the square of 2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+4x+4=4+4
Square 2.
x^{2}+4x+4=8
Add 4 to 4.
\left(x+2\right)^{2}=8
Factor x^{2}+4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+2\right)^{2}}=\sqrt{8}
Take the square root of both sides of the equation.
x+2=2\sqrt{2} x+2=-2\sqrt{2}
Simplify.
x=2\sqrt{2}-2 x=-2\sqrt{2}-2
Subtract 2 from both sides of the equation.