Solve 47^2-3^2/27^2+2*27*23+23^2

$$\frac{ { 47 }^{ 2 } - { 3 }^{ 2 } }{ { 27 }^{ 2 } +2 \times 27 \times 23+ { 23 }^{ 2 } }$$

Evaluate

$$\frac{22}{25}=0.88$$

Solution Steps

Calculate 47 to the power of 2 and get 2209.

$$\frac{2209-3^{2}}{27^{2}+2\times 27\times 23+23^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{2209-9}{27^{2}+2\times 27\times 23+23^{2}}$$

Subtract 9 from 2209 to get 2200.

$$\frac{2200}{27^{2}+2\times 27\times 23+23^{2}}$$

Calculate 27 to the power of 2 and get 729.

$$\frac{2200}{729+2\times 27\times 23+23^{2}}$$

Multiply 2 and 27 to get 54.

$$\frac{2200}{729+54\times 23+23^{2}}$$

Multiply 54 and 23 to get 1242.

$$\frac{2200}{729+1242+23^{2}}$$

Add 729 and 1242 to get 1971.

$$\frac{2200}{1971+23^{2}}$$

Calculate 23 to the power of 2 and get 529.

$$\frac{2200}{1971+529}$$

Add 1971 and 529 to get 2500.

$$\frac{2200}{2500}$$

Reduce the fraction \frac{2200}{2500} to lowest terms by extracting and canceling out 100.

$$\frac{22}{25}$$

Factor

$$\frac{2 \cdot 11}{5 ^ {2}} = 0.88$$