Solve 4^3-10+-4/5^2--4-5

$$\frac{ { 4 }^{ 3 } -10+-4 }{ { 5 }^{ 2 } --4-5 }$$

Evaluate

$$\frac{25}{12}\approx 2.083333333$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$\frac{64-10-4}{5^{2}-\left(-4\right)-5}$$

Subtract 10 from 64 to get 54.

$$\frac{54-4}{5^{2}-\left(-4\right)-5}$$

Subtract 4 from 54 to get 50.

$$\frac{50}{5^{2}-\left(-4\right)-5}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{50}{25-\left(-4\right)-5}$$

The opposite of -4 is 4.

$$\frac{50}{25+4-5}$$

Add 25 and 4 to get 29.

$$\frac{50}{29-5}$$

Subtract 5 from 29 to get 24.

$$\frac{50}{24}$$

Reduce the fraction \frac{50}{24} to lowest terms by extracting and canceling out 2.

$$\frac{25}{12}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {2} \cdot 3} = 2\frac{1}{12} = 2.0833333333333335$$