Solve 4^2/4^2+6x=4^2/4^2+63=

$$\frac{ { 4 }^{ 2 } }{ { 4 }^{ 2 } } +6x= \frac{ { 4 }^{ 2 } }{ { 4 }^{ 2 } } +63=$$

Solve for x

$$x = \frac{21}{2} = 10\frac{1}{2} = 10.5$$

Steps for Solving Linear Equation

Cancel out 4^{2} in both numerator and denominator.

$$1+6x=\frac{4^{2}}{4^{2}}+63$$

Cancel out 4^{2} in both numerator and denominator.

$$1+6x=1+63$$

Add 1 and 63 to get 64.

$$1+6x=64$$

Subtract 1 from both sides.

$$6x=64-1$$

Subtract 1 from 64 to get 63.

$$6x=63$$

Divide both sides by 6.

$$x=\frac{63}{6}$$

Reduce the fraction \frac{63}{6} to lowest terms by extracting and canceling out 3.

$$x=\frac{21}{2}$$