Solve 33334^3+22222^3/33334^3+11112^3

$$\frac{ { 33334 }^{ 3 } + { 22222 }^{ 3 } }{ { 33334 }^{ 3 } + { 11112 }^{ 3 } }$$

Evaluate

$$\frac{27778}{22223}\approx 1.249966251$$

Solution Steps

Calculate 33334 to the power of 3 and get 37039259303704.

$$\frac{37039259303704+22222^{3}}{33334^{3}+11112^{3}}$$

Calculate 22222 to the power of 3 and get 10973607685048.

$$\frac{37039259303704+10973607685048}{33334^{3}+11112^{3}}$$

Add 37039259303704 and 10973607685048 to get 48012866988752.

$$\frac{48012866988752}{33334^{3}+11112^{3}}$$

Calculate 33334 to the power of 3 and get 37039259303704.

$$\frac{48012866988752}{37039259303704+11112^{3}}$$

Calculate 11112 to the power of 3 and get 1372071356928.

$$\frac{48012866988752}{37039259303704+1372071356928}$$

Add 37039259303704 and 1372071356928 to get 38411330660632.

$$\frac{48012866988752}{38411330660632}$$

Reduce the fraction \frac{48012866988752}{38411330660632} to lowest terms by extracting and canceling out 1728449384.

$$\frac{27778}{22223}$$

Factor

$$\frac{2 \cdot 17 \cdot 19 \cdot 43}{71 \cdot 313} = 1\frac{5555}{22223} = 1.2499662511812086$$