Solve {left(frac{3+4^2*5-3^3/7right)}^3}{8^2}+2^3

$$\frac{ { \left( \frac{ 3+ { 4 }^{ 2 } \times 5- { 3 }^{ 3 } }{ 7 } \right) }^{ 3 } }{ { 8 }^{ 2 } } + { 2 }^{ 3 }$$

Evaluate

$$16$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{\left(\frac{3+16\times 5-3^{3}}{7}\right)^{3}}{8^{2}}+2^{3}$$

Multiply 16 and 5 to get 80.

$$\frac{\left(\frac{3+80-3^{3}}{7}\right)^{3}}{8^{2}}+2^{3}$$

Add 3 and 80 to get 83.

$$\frac{\left(\frac{83-3^{3}}{7}\right)^{3}}{8^{2}}+2^{3}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{\left(\frac{83-27}{7}\right)^{3}}{8^{2}}+2^{3}$$

Subtract 27 from 83 to get 56.

$$\frac{\left(\frac{56}{7}\right)^{3}}{8^{2}}+2^{3}$$

Divide 56 by 7 to get 8.

$$\frac{8^{3}}{8^{2}}+2^{3}$$

Calculate 8 to the power of 3 and get 512.

$$\frac{512}{8^{2}}+2^{3}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{512}{64}+2^{3}$$

Divide 512 by 64 to get 8.

$$8+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$8+8$$

Add 8 and 8 to get 16.

$$16$$

Factor

$$2^{4}$$