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\frac{\sqrt{\frac{39}{8}}}{1}
Reduce the fraction \frac{78}{16} to lowest terms by extracting and canceling out 2.
\frac{\frac{\sqrt{39}}{\sqrt{8}}}{1}
Rewrite the square root of the division \sqrt{\frac{39}{8}} as the division of square roots \frac{\sqrt{39}}{\sqrt{8}}.
\frac{\frac{\sqrt{39}}{2\sqrt{2}}}{1}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{\frac{\sqrt{39}\sqrt{2}}{2\left(\sqrt{2}\right)^{2}}}{1}
Rationalize the denominator of \frac{\sqrt{39}}{2\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\frac{\sqrt{39}\sqrt{2}}{2\times 2}}{1}
The square of \sqrt{2} is 2.
\frac{\frac{\sqrt{78}}{2\times 2}}{1}
To multiply \sqrt{39} and \sqrt{2}, multiply the numbers under the square root.
\frac{\frac{\sqrt{78}}{4}}{1}
Multiply 2 and 2 to get 4.
\frac{\sqrt{78}}{4}
Anything divided by one gives itself.