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\frac{\sqrt{6}}{2\sqrt{3}}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{\sqrt{6}\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{6}}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{6}\sqrt{3}}{2\times 3}
The square of \sqrt{3} is 3.
\frac{\sqrt{3}\sqrt{2}\sqrt{3}}{2\times 3}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{3\sqrt{2}}{2\times 3}
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{3\sqrt{2}}{6}
Multiply 2 and 3 to get 6.
\frac{1}{2}\sqrt{2}
Divide 3\sqrt{2} by 6 to get \frac{1}{2}\sqrt{2}.