Solve frac{sqrt{49}}{12}+12/3-42=

$$\frac{ \sqrt{ 49 } }{ 12 } + \frac{ 12 }{ 3 } -42=$$

Evaluate

$$-\frac{449}{12}\approx -37.416666667$$

Solution Steps

Calculate the square root of 49 and get 7.

$$\frac{7}{12}+\frac{12}{3}-42$$

Divide 12 by 3 to get 4.

$$\frac{7}{12}+4-42$$

Convert 4 to fraction \frac{48}{12}.

$$\frac{7}{12}+\frac{48}{12}-42$$

Since \frac{7}{12} and \frac{48}{12} have the same denominator, add them by adding their numerators.

$$\frac{7+48}{12}-42$$

Add 7 and 48 to get 55.

$$\frac{55}{12}-42$$

Convert 42 to fraction \frac{504}{12}.

$$\frac{55}{12}-\frac{504}{12}$$

Since \frac{55}{12} and \frac{504}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{55-504}{12}$$

Subtract 504 from 55 to get -449.

$$-\frac{449}{12}$$

Factor

$$-\frac{449}{12} = -37\frac{5}{12} = -37.416666666666664$$