Solve sqrt[3]{{left(frac{7/8right)}^2}}{{left(1-3/4right)}^-2}

$$\frac{ \sqrt[3]{ { \left( \frac{ 7 }{ 8 } \right) }^{ 2 } } }{ { \left(1- \frac{ 3 }{ 4 } \right) }^{ -2 } }$$

Evaluate

$$\frac{7^{\frac{2}{3}}}{64}\approx 0.057176652$$

Solution Steps

Calculate \frac{7}{8} to the power of 2 and get \frac{49}{64}.

$$\frac{\sqrt[3]{\frac{49}{64}}}{\left(1-\frac{3}{4}\right)^{-2}}$$

Subtract \frac{3}{4} from 1 to get \frac{1}{4}.

$$\frac{\sqrt[3]{\frac{49}{64}}}{\left(\frac{1}{4}\right)^{-2}}$$

Calculate \frac{1}{4} to the power of -2 and get 16.

$$\frac{\sqrt[3]{\frac{49}{64}}}{16}$$