Solve left(5+3*2/2right)left(4/2-3+6right)/{left(7-frac{8{2}2-2right)}^2}

$$\frac{ \left( 5+ \frac{ 3 \cdot 2 }{ 2 } \right) \left( \frac{ 4 }{ 2 } -3+6 \right) }{ { \left(7- \frac{ 8 }{ 2 } 2-2 \right) }^{ 2 } }$$

Evaluate

$$\frac{40}{9}\approx 4.444444444$$

Solution Steps

Cancel out 2 and 2.

$$\frac{\left(5+3\right)\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}\times 2-2\right)^{2}}$$

Add 5 and 3 to get 8.

$$\frac{8\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}\times 2-2\right)^{2}}$$

Divide 4 by 2 to get 2.

$$\frac{8\left(2-3+6\right)}{\left(7-\frac{8}{2}\times 2-2\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$\frac{8\left(-1+6\right)}{\left(7-\frac{8}{2}\times 2-2\right)^{2}}$$

Add -1 and 6 to get 5.

$$\frac{8\times 5}{\left(7-\frac{8}{2}\times 2-2\right)^{2}}$$

Multiply 8 and 5 to get 40.

$$\frac{40}{\left(7-\frac{8}{2}\times 2-2\right)^{2}}$$

Divide 8 by 2 to get 4.

$$\frac{40}{\left(7-4\times 2-2\right)^{2}}$$

Multiply 4 and 2 to get 8.

$$\frac{40}{\left(7-8-2\right)^{2}}$$

Subtract 8 from 7 to get -1.

$$\frac{40}{\left(-1-2\right)^{2}}$$

Subtract 2 from -1 to get -3.

$$\frac{40}{\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{40}{9}$$

Factor

$$\frac{2 ^ {3} \cdot 5}{3 ^ {2}} = 4\frac{4}{9} = 4.444444444444445$$