Solve 8/5/frac{2{25}-5/16}=frac{8/5}{-frac{93}{400}}

$$\frac{ \frac{ 8 }{ 5 } }{ \frac{ 2 }{ 25 } - \frac{ 5 }{ 16 } } = \frac{ \frac{ 8 }{ 5 } }{ - \frac{ 93 }{ 400 } }$$

Verify

Solution Steps

Least common multiple of 25 and 16 is 400. Convert \frac{2}{25} and \frac{5}{16} to fractions with denominator 400.

$$\frac{\frac{8}{5}}{\frac{32}{400}-\frac{125}{400}}=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Since \frac{32}{400} and \frac{125}{400} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{8}{5}}{\frac{32-125}{400}}=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Subtract 125 from 32 to get -93.

$$\frac{\frac{8}{5}}{-\frac{93}{400}}=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Divide \frac{8}{5} by -\frac{93}{400} by multiplying \frac{8}{5} by the reciprocal of -\frac{93}{400}.

$$\frac{8}{5}\left(-\frac{400}{93}\right)=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Multiply \frac{8}{5} times -\frac{400}{93} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\left(-400\right)}{5\times 93}=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Do the multiplications in the fraction \frac{8\left(-400\right)}{5\times 93}.

$$\frac{-3200}{465}=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Reduce the fraction \frac{-3200}{465} to lowest terms by extracting and canceling out 5.

$$-\frac{640}{93}=\frac{\frac{8}{5}}{-\frac{93}{400}}$$

Divide \frac{8}{5} by -\frac{93}{400} by multiplying \frac{8}{5} by the reciprocal of -\frac{93}{400}.

$$-\frac{640}{93}=\frac{8}{5}\left(-\frac{400}{93}\right)$$

Multiply \frac{8}{5} times -\frac{400}{93} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{640}{93}=\frac{8\left(-400\right)}{5\times 93}$$

Do the multiplications in the fraction \frac{8\left(-400\right)}{5\times 93}.

$$-\frac{640}{93}=\frac{-3200}{465}$$

Reduce the fraction \frac{-3200}{465} to lowest terms by extracting and canceling out 5.

$$-\frac{640}{93}=-\frac{640}{93}$$

Compare -\frac{640}{93} and -\frac{640}{93}.

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