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\frac{20000+355.16\times 93.8}{\left(\frac{20000}{190}+93.8\right)\times 7}
Express \frac{\frac{20000+355.16\times 93.8}{\frac{20000}{190}+93.8}}{7} as a single fraction.
\frac{20000+33314.008}{\left(\frac{20000}{190}+93.8\right)\times 7}
Multiply 355.16 and 93.8 to get 33314.008.
\frac{53314.008}{\left(\frac{20000}{190}+93.8\right)\times 7}
Add 20000 and 33314.008 to get 53314.008.
\frac{53314.008}{\left(\frac{2000}{19}+93.8\right)\times 7}
Reduce the fraction \frac{20000}{190} to lowest terms by extracting and canceling out 10.
\frac{53314.008}{\left(\frac{2000}{19}+\frac{469}{5}\right)\times 7}
Convert decimal number 93.8 to fraction \frac{938}{10}. Reduce the fraction \frac{938}{10} to lowest terms by extracting and canceling out 2.
\frac{53314.008}{\left(\frac{10000}{95}+\frac{8911}{95}\right)\times 7}
Least common multiple of 19 and 5 is 95. Convert \frac{2000}{19} and \frac{469}{5} to fractions with denominator 95.
\frac{53314.008}{\frac{10000+8911}{95}\times 7}
Since \frac{10000}{95} and \frac{8911}{95} have the same denominator, add them by adding their numerators.
\frac{53314.008}{\frac{18911}{95}\times 7}
Add 10000 and 8911 to get 18911.
\frac{53314.008}{\frac{18911\times 7}{95}}
Express \frac{18911}{95}\times 7 as a single fraction.
\frac{53314.008}{\frac{132377}{95}}
Multiply 18911 and 7 to get 132377.
53314.008\times \frac{95}{132377}
Divide 53314.008 by \frac{132377}{95} by multiplying 53314.008 by the reciprocal of \frac{132377}{95}.
\frac{6664251}{125}\times \frac{95}{132377}
Convert decimal number 53314.008 to fraction \frac{53314008}{1000}. Reduce the fraction \frac{53314008}{1000} to lowest terms by extracting and canceling out 8.
\frac{6664251\times 95}{125\times 132377}
Multiply \frac{6664251}{125} times \frac{95}{132377} by multiplying numerator times numerator and denominator times denominator.
\frac{633103845}{16547125}
Do the multiplications in the fraction \frac{6664251\times 95}{125\times 132377}.
\frac{126620769}{3309425}
Reduce the fraction \frac{633103845}{16547125} to lowest terms by extracting and canceling out 5.