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\frac{\left(2x^{2}-128\right)\left(3x^{2}+30x+48\right)}{\left(x^{2}+16x+64\right)\left(x^{2}-6x-16\right)}
Divide \frac{2x^{2}-128}{x^{2}+16x+64} by \frac{x^{2}-6x-16}{3x^{2}+30x+48} by multiplying \frac{2x^{2}-128}{x^{2}+16x+64} by the reciprocal of \frac{x^{2}-6x-16}{3x^{2}+30x+48}.
\frac{2\times 3\left(x-8\right)\left(x+2\right)\left(x+8\right)^{2}}{\left(x-8\right)\left(x+2\right)\left(x+8\right)^{2}}
Factor the expressions that are not already factored.
2\times 3
Cancel out \left(x-8\right)\left(x+2\right)\left(x+8\right)^{2} in both numerator and denominator.
6
Multiply 2 and 3 to get 6.