Solve for y
y=16
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\frac{y-0}{12}\times \frac{9-0}{12-24}=-1
Subtract 0 from 12 to get 12.
\frac{y-0}{12}\times \frac{9}{12-24}=-1
Subtract 0 from 9 to get 9.
\frac{y-0}{12}\times \frac{9}{-12}=-1
Subtract 24 from 12 to get -12.
\frac{y-0}{12}\left(-\frac{3}{4}\right)=-1
Reduce the fraction \frac{9}{-12} to lowest terms by extracting and canceling out 3.
\frac{-\left(y-0\right)\times 3}{12\times 4}=-1
Multiply \frac{y-0}{12} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.
\frac{-y}{4\times 4}=-1
Cancel out 3 in both numerator and denominator.
\frac{-y}{16}=-1
Multiply 4 and 4 to get 16.
-y=-16
Multiply both sides by 16.
y=16
Cancel out -1 on both sides.
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Limits
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