Solve y-(-2)/0-(-2)=x-7/8-7=

$$\frac { y - ( - 2 ) } { 0 - ( - 2 ) } = \frac { x - 7 } { 8 - 7 } =$$

Solve for x

$$x=\frac{y+16}{2}$$

Solution Steps

The opposite of -2 is 2.

$$\frac{y+2}{0-\left(-2\right)}=\frac{x-7}{8-7}$$

The opposite of -2 is 2.

$$\frac{y+2}{0+2}=\frac{x-7}{8-7}$$

Add 0 and 2 to get 2.

$$\frac{y+2}{2}=\frac{x-7}{8-7}$$

Subtract 7 from 8 to get 1.

$$\frac{y+2}{2}=\frac{x-7}{1}$$

Anything divided by one gives itself.

$$\frac{y+2}{2}=x-7$$

Divide each term of y+2 by 2 to get \frac{1}{2}y+1.

$$\frac{1}{2}y+1=x-7$$

Swap sides so that all variable terms are on the left hand side.

$$x-7=\frac{1}{2}y+1$$

Add 7 to both sides.

$$x=\frac{1}{2}y+1+7$$

Add 1 and 7 to get 8.

$$x=\frac{1}{2}y+8$$

Solve for y

$$y=2\left(x-8\right)$$

Steps for Solving Linear Equation

The opposite of -2 is 2.

$$\frac{y+2}{0-\left(-2\right)}=\frac{x-7}{8-7}$$

The opposite of -2 is 2.

$$\frac{y+2}{0+2}=\frac{x-7}{8-7}$$

Add 0 and 2 to get 2.

$$\frac{y+2}{2}=\frac{x-7}{8-7}$$

Subtract 7 from 8 to get 1.

$$\frac{y+2}{2}=\frac{x-7}{1}$$

Anything divided by one gives itself.

$$\frac{y+2}{2}=x-7$$

Divide each term of y+2 by 2 to get \frac{1}{2}y+1.

$$\frac{1}{2}y+1=x-7$$

Subtract 1 from both sides.

$$\frac{1}{2}y=x-7-1$$

Subtract 1 from -7 to get -8.

$$\frac{1}{2}y=x-8$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{x-8}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{x-8}{\frac{1}{2}}$$

Divide x-8 by \frac{1}{2} by multiplying x-8 by the reciprocal of \frac{1}{2}.

$$y=2x-16$$