Solve for x
x=-3y-3
y\neq -1
Solve for y
y=-\frac{x}{3}-1
x\neq 0
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3\left(y+1\right)=-x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x, the least common multiple of x,3.
3y+3=-x
Use the distributive property to multiply 3 by y+1.
-x=3y+3
Swap sides so that all variable terms are on the left hand side.
\frac{-x}{-1}=\frac{3y+3}{-1}
Divide both sides by -1.
x=\frac{3y+3}{-1}
Dividing by -1 undoes the multiplication by -1.
x=-3y-3
Divide 3+3y by -1.
x=-3y-3\text{, }x\neq 0
Variable x cannot be equal to 0.
3\left(y+1\right)=-x
Multiply both sides of the equation by 3x, the least common multiple of x,3.
3y+3=-x
Use the distributive property to multiply 3 by y+1.
3y=-x-3
Subtract 3 from both sides.
\frac{3y}{3}=\frac{-x-3}{3}
Divide both sides by 3.
y=\frac{-x-3}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{x}{3}-1
Divide -x-3 by 3.
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