Solve y+1/(y+1)^2+3/(y+1)

$$\frac { y + 1 } { ( y + 1 ) ^ { 2 } } + \frac { 3 } { ( y + 1 ) }$$

Evaluate

$$\frac{4}{y+1}$$

Solution Steps

Rewrite \left(y+1\right)^{2} as \left(y+1\right)\left(y+1\right). Cancel out y+1 in both numerator and denominator.

$$\frac{1}{y+1}+\frac{3}{y+1}$$

Since \frac{1}{y+1} and \frac{3}{y+1} have the same denominator, add them by adding their numerators. Add 1 and 3 to get 4.

$$\frac{4}{y+1}$$

Expand

$$\frac{4}{y+1}$$

Solution Steps

Rewrite \left(y+1\right)^{2} as \left(y+1\right)\left(y+1\right). Cancel out y+1 in both numerator and denominator.

$$\frac{1}{y+1}+\frac{3}{y+1}$$

Since \frac{1}{y+1} and \frac{3}{y+1} have the same denominator, add them by adding their numerators. Add 1 and 3 to get 4.

$$\frac{4}{y+1}$$