Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

x-2>0 x+5<0
For the quotient to be negative, x-2 and x+5 have to be of the opposite signs. Consider the case when x-2 is positive and x+5 is negative.
x\in \emptyset
This is false for any x.
x+5>0 x-2<0
Consider the case when x+5 is positive and x-2 is negative.
x\in \left(-5,2\right)
The solution satisfying both inequalities is x\in \left(-5,2\right).
x\in \left(-5,2\right)
The final solution is the union of the obtained solutions.