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\frac{x-1}{3}=3
Add 1 and 2 to get 3.
\frac{1}{3}x-\frac{1}{3}=3
Divide each term of x-1 by 3 to get \frac{1}{3}x-\frac{1}{3}.
\frac{1}{3}x=3+\frac{1}{3}
Add \frac{1}{3} to both sides.
\frac{1}{3}x=\frac{9}{3}+\frac{1}{3}
Convert 3 to fraction \frac{9}{3}.
\frac{1}{3}x=\frac{9+1}{3}
Since \frac{9}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.
\frac{1}{3}x=\frac{10}{3}
Add 9 and 1 to get 10.
x=\frac{10}{3}\times 3
Multiply both sides by 3, the reciprocal of \frac{1}{3}.
x=10
Cancel out 3 and 3.