Solve x/b-2=c

$$\frac { x } { b } - 2 = c$$

Solve for b

$$\left\{\begin{matrix}b=\frac{x}{c+2}\text{, }&x\neq 0\text{ and }c\neq -2\\b\neq 0\text{, }&c=-2\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by b.

$$x+b\left(-2\right)=cb$$

Subtract cb from both sides.

$$x+b\left(-2\right)-cb=0$$

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$b\left(-2\right)-cb=-x$$

Combine all terms containing b.

$$\left(-2-c\right)b=-x$$

The equation is in standard form.

$$\left(-c-2\right)b=-x$$

Divide both sides by -2-c.

$$\frac{\left(-c-2\right)b}{-c-2}=-\frac{x}{-c-2}$$

Dividing by -2-c undoes the multiplication by -2-c.

$$b=-\frac{x}{-c-2}$$

Divide -x by -2-c.

$$b=\frac{x}{c+2}$$

Variable b cannot be equal to 0.

$$b=\frac{x}{c+2}\text{, }b\neq 0$$

Solve for c

$$c=\frac{x}{b}-2$$

$$b\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by b.

$$x+b\left(-2\right)=cb$$

Swap sides so that all variable terms are on the left hand side.

$$cb=x+b\left(-2\right)$$

The equation is in standard form.

$$bc=x-2b$$

Divide both sides by b.

$$\frac{bc}{b}=\frac{x-2b}{b}$$

Dividing by b undoes the multiplication by b.

$$c=\frac{x-2b}{b}$$

Divide x-2b by b.

$$c=\frac{x}{b}-2$$