Solve x/4-3y/2=10

$$\frac { x } { 4 } - \frac { 3 y } { 2 } = 10$$

Solve for x

$$x=6y+40$$

Solution Steps

Multiply both sides of the equation by 4, the least common multiple of 4,2.

$$x-2\times 3y=40$$

Multiply -2 and 3 to get -6.

$$x-6y=40$$

Add 6y to both sides.

$$x=40+6y$$

Solve for y

$$y=\frac{x-40}{6}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4, the least common multiple of 4,2.

$$x-2\times 3y=40$$

Multiply -2 and 3 to get -6.

$$x-6y=40$$

Subtract x from both sides.

$$-6y=40-x$$

Divide both sides by -6.

$$\frac{-6y}{-6}=\frac{40-x}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$y=\frac{40-x}{-6}$$

Divide 40-x by -6.

$$y=\frac{x}{6}-\frac{20}{3}$$