Solve x/4=2/3quadtext{u}quadx+y=40

$$\frac { x } { 4 } = \frac { 2 } { 3 } \quad \text { u } \quad x + y = 40$$

Solve for x, y

$$x = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$$

$$y = \frac{112}{3} = 37\frac{1}{3} \approx 37.333333333$$

Solution Steps

Consider the first equation. Multiply both sides by 4.

$$x=\frac{2}{3}\times 4$$

Multiply \frac{2}{3} and 4 to get \frac{8}{3}.

$$x=\frac{8}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$\frac{8}{3}+y=40$$

Subtract \frac{8}{3} from both sides.

$$y=40-\frac{8}{3}$$

Subtract \frac{8}{3} from 40 to get \frac{112}{3}.

$$y=\frac{112}{3}$$

The system is now solved.

$$x=\frac{8}{3} y=\frac{112}{3}$$