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\left(2x+3\right)x=\left(3x+1\right)\left(x-1\right)
Variable x cannot be equal to any of the values -\frac{3}{2},-\frac{1}{3} since division by zero is not defined. Multiply both sides of the equation by \left(2x+3\right)\left(3x+1\right), the least common multiple of 3x+1,2x+3.
2x^{2}+3x=\left(3x+1\right)\left(x-1\right)
Use the distributive property to multiply 2x+3 by x.
2x^{2}+3x=3x^{2}-2x-1
Use the distributive property to multiply 3x+1 by x-1 and combine like terms.
2x^{2}+3x-3x^{2}=-2x-1
Subtract 3x^{2} from both sides.
-x^{2}+3x=-2x-1
Combine 2x^{2} and -3x^{2} to get -x^{2}.
-x^{2}+3x+2x=-1
Add 2x to both sides.
-x^{2}+5x=-1
Combine 3x and 2x to get 5x.
-x^{2}+5x+1=0
Add 1 to both sides.
x=\frac{-5±\sqrt{5^{2}-4\left(-1\right)}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 5 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-5±\sqrt{25-4\left(-1\right)}}{2\left(-1\right)}
Square 5.
x=\frac{-5±\sqrt{25+4}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-5±\sqrt{29}}{2\left(-1\right)}
Add 25 to 4.
x=\frac{-5±\sqrt{29}}{-2}
Multiply 2 times -1.
x=\frac{\sqrt{29}-5}{-2}
Now solve the equation x=\frac{-5±\sqrt{29}}{-2} when ± is plus. Add -5 to \sqrt{29}.
x=\frac{5-\sqrt{29}}{2}
Divide -5+\sqrt{29} by -2.
x=\frac{-\sqrt{29}-5}{-2}
Now solve the equation x=\frac{-5±\sqrt{29}}{-2} when ± is minus. Subtract \sqrt{29} from -5.
x=\frac{\sqrt{29}+5}{2}
Divide -5-\sqrt{29} by -2.
x=\frac{5-\sqrt{29}}{2} x=\frac{\sqrt{29}+5}{2}
The equation is now solved.
\left(2x+3\right)x=\left(3x+1\right)\left(x-1\right)
Variable x cannot be equal to any of the values -\frac{3}{2},-\frac{1}{3} since division by zero is not defined. Multiply both sides of the equation by \left(2x+3\right)\left(3x+1\right), the least common multiple of 3x+1,2x+3.
2x^{2}+3x=\left(3x+1\right)\left(x-1\right)
Use the distributive property to multiply 2x+3 by x.
2x^{2}+3x=3x^{2}-2x-1
Use the distributive property to multiply 3x+1 by x-1 and combine like terms.
2x^{2}+3x-3x^{2}=-2x-1
Subtract 3x^{2} from both sides.
-x^{2}+3x=-2x-1
Combine 2x^{2} and -3x^{2} to get -x^{2}.
-x^{2}+3x+2x=-1
Add 2x to both sides.
-x^{2}+5x=-1
Combine 3x and 2x to get 5x.
\frac{-x^{2}+5x}{-1}=-\frac{1}{-1}
Divide both sides by -1.
x^{2}+\frac{5}{-1}x=-\frac{1}{-1}
Dividing by -1 undoes the multiplication by -1.
x^{2}-5x=-\frac{1}{-1}
Divide 5 by -1.
x^{2}-5x=1
Divide -1 by -1.
x^{2}-5x+\left(-\frac{5}{2}\right)^{2}=1+\left(-\frac{5}{2}\right)^{2}
Divide -5, the coefficient of the x term, by 2 to get -\frac{5}{2}. Then add the square of -\frac{5}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-5x+\frac{25}{4}=1+\frac{25}{4}
Square -\frac{5}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-5x+\frac{25}{4}=\frac{29}{4}
Add 1 to \frac{25}{4}.
\left(x-\frac{5}{2}\right)^{2}=\frac{29}{4}
Factor x^{2}-5x+\frac{25}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{5}{2}\right)^{2}}=\sqrt{\frac{29}{4}}
Take the square root of both sides of the equation.
x-\frac{5}{2}=\frac{\sqrt{29}}{2} x-\frac{5}{2}=-\frac{\sqrt{29}}{2}
Simplify.
x=\frac{\sqrt{29}+5}{2} x=\frac{5-\sqrt{29}}{2}
Add \frac{5}{2} to both sides of the equation.