Solve x/2*7*2^2*sqrt{12}+x^-2

$$\frac { x } { 2 } \times 7 \cdot 2 ^ { 2 } \times \sqrt { 12 } + x ^ { - 2 }$$

Evaluate

$$28\sqrt{3}x+\frac{1}{x^{2}}$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$7\times \frac{x}{2}\times 4\sqrt{12}+x^{-2}$$

Multiply 7 and 4 to get 28.

$$28\times \frac{x}{2}\sqrt{12}+x^{-2}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$28\times \frac{x}{2}\times 2\sqrt{3}+x^{-2}$$

Multiply 28 and 2 to get 56.

$$56\times \frac{x}{2}\sqrt{3}+x^{-2}$$

Cancel out 2, the greatest common factor in 56 and 2.

$$28x\sqrt{3}+x^{-2}$$

Factor

$$\frac{28\sqrt{3}x^{3}+1}{x^{2}}$$