Solve x/17=y^x/18

$$\frac { x } { 17 } = \frac { y ^ { x } } { 18 }$$

Solve for y (complex solution)

$$y=e^{\frac{Im(x)arg(x)+iRe(x)arg(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}-\frac{2\pi n_{1}iRe(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}-\frac{2\pi n_{1}Im(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}}\times \left(\frac{18|x|}{17}\right)^{\frac{Re(x)-iIm(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}}$$

$$n_{1}\in \mathrm{Z}$$

Solve for y

$$\left\{\begin{matrix}y=\left(\frac{18x}{17}\right)^{\frac{1}{x}}\text{, }&\left(Numerator(x)\text{bmod}2=1\text{ and }x<0\text{ and }Denominator(x)\text{bmod}2=1\right)\text{ or }\left(\left(\frac{18x}{17}\right)^{\frac{1}{x}}<0\text{ and }x>0\text{ and }Denominator(x)\text{bmod}2=1\right)\text{ or }\left(\left(\frac{18x}{17}\right)^{\frac{1}{x}}>0\text{ and }x>0\right)\\y=-\left(\frac{18x}{17}\right)^{\frac{1}{x}}\text{, }&\left(Numerator(x)\text{bmod}2=1\text{ and }x<0\text{ and }Numerator(x)\text{bmod}2=0\text{ and }Denominator(x)\text{bmod}2=1\right)\text{ or }\left(x>0\text{ and }\left(\frac{18x}{17}\right)^{\frac{1}{x}}>0\text{ and }Numerator(x)\text{bmod}2=0\text{ and }Denominator(x)\text{bmod}2=1\right)\text{ or }\left(x>0\text{ and }\left(\frac{18x}{17}\right)^{\frac{1}{x}}<0\text{ and }Numerator(x)\text{bmod}2=0\right)\end{matrix}\right.$$