Solve for a
a=\frac{1-x-x^{3}}{2}
x\neq \sqrt[3]{\frac{\sqrt{93}}{18}+\frac{1}{2}}+\sqrt[3]{-\frac{\sqrt{93}}{18}+\frac{1}{2}}\text{ and }x\neq \frac{18^{\frac{2}{3}}\left(\sqrt[3]{\sqrt{93}+9}+\sqrt[3]{9-\sqrt{93}}\right)}{18}
Solve for x
x=\frac{\sqrt[3]{3}\times 2^{\frac{2}{3}}\left(\sqrt[3]{\sqrt{3\left(108a^{2}-108a+31\right)}-18a+9}+\sqrt[3]{-\sqrt{3\left(108a^{2}-108a+31\right)}-18a+9}\right)}{6}
a\neq 0
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x^{3}+x-1+2a=0
Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a.
x-1+2a=-x^{3}
Subtract x^{3} from both sides. Anything subtracted from zero gives its negation.
-1+2a=-x^{3}-x
Subtract x from both sides.
2a=-x^{3}-x+1
Add 1 to both sides.
2a=1-x-x^{3}
The equation is in standard form.
\frac{2a}{2}=\frac{1-x-x^{3}}{2}
Divide both sides by 2.
a=\frac{1-x-x^{3}}{2}
Dividing by 2 undoes the multiplication by 2.
a=\frac{1-x-x^{3}}{2}\text{, }a\neq 0
Variable a cannot be equal to 0.
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