Solve x^2-25/x+1*x^2-3x-4/x^2+x-20=

$$\frac { x ^ { 2 } - 25 } { x + 1 } \cdot \frac { x ^ { 2 } - 3 x - 4 } { x ^ { 2 } + x - 20 } =$$

Evaluate

$$x-5$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{x^{2}-3x-4}{x^{2}+x-20}.

$$\frac{x^{2}-25}{x+1}\times \frac{\left(x-4\right)\left(x+1\right)}{\left(x-4\right)\left(x+5\right)}$$

Cancel out x-4 in both numerator and denominator.

$$\frac{x^{2}-25}{x+1}\times \frac{x+1}{x+5}$$

Multiply \frac{x^{2}-25}{x+1} times \frac{x+1}{x+5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(x^{2}-25\right)\left(x+1\right)}{\left(x+1\right)\left(x+5\right)}$$

Cancel out x+1 in both numerator and denominator.

$$\frac{x^{2}-25}{x+5}$$

Factor the expressions that are not already factored.

$$\frac{\left(x-5\right)\left(x+5\right)}{x+5}$$

Cancel out x+5 in both numerator and denominator.

$$x-5$$

Expand

$$x-5$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{x^{2}-3x-4}{x^{2}+x-20}.

$$\frac{x^{2}-25}{x+1}\times \frac{\left(x-4\right)\left(x+1\right)}{\left(x-4\right)\left(x+5\right)}$$

Cancel out x-4 in both numerator and denominator.

$$\frac{x^{2}-25}{x+1}\times \frac{x+1}{x+5}$$

Multiply \frac{x^{2}-25}{x+1} times \frac{x+1}{x+5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(x^{2}-25\right)\left(x+1\right)}{\left(x+1\right)\left(x+5\right)}$$

Cancel out x+1 in both numerator and denominator.

$$\frac{x^{2}-25}{x+5}$$

Factor the expressions that are not already factored.

$$\frac{\left(x-5\right)\left(x+5\right)}{x+5}$$

Cancel out x+5 in both numerator and denominator.

$$x-5$$