Solve for x
x\in \begin{bmatrix}-\sqrt{35},\sqrt{35}\end{bmatrix}
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x^{2}\leq 5\times 7
Multiply both sides by 7. Since 7 is positive, the inequality direction remains the same.
x^{2}\leq 35
Multiply 5 and 7 to get 35.
x^{2}\leq \left(\sqrt{35}\right)^{2}
Calculate the square root of 35 and get \sqrt{35}. Rewrite 35 as \left(\sqrt{35}\right)^{2}.
|x|\leq \sqrt{35}
Inequality holds for |x|\leq \sqrt{35}.
x\in \begin{bmatrix}-\sqrt{35},\sqrt{35}\end{bmatrix}
Rewrite |x|\leq \sqrt{35} as x\in \left[-\sqrt{35},\sqrt{35}\right].
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