Solve x^2/2=y-4/-8

$$\frac { x ^ { 2 } } { 2 } = \frac { y - 4 } { - 8 }$$

Solve for y

$$y=4-4x^{2}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8, the least common multiple of 2,-8.

$$4x^{2}=-\left(y-4\right)$$

To find the opposite of y-4, find the opposite of each term.

$$4x^{2}=-y+4$$

Swap sides so that all variable terms are on the left hand side.

$$-y+4=4x^{2}$$

Subtract 4 from both sides.

$$-y=4x^{2}-4$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{4x^{2}-4}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{4x^{2}-4}{-1}$$

Divide -4+4x^{2} by -1.

$$y=4-4x^{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{4-y}}{2}$$

$$x=\frac{\sqrt{4-y}}{2}$$

Solve for x

$$x=\frac{\sqrt{4-y}}{2}$$

$$x=-\frac{\sqrt{4-y}}{2}\text{, }y\leq 4$$