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\frac{1}{3}x+\frac{1}{3}y=M
Divide each term of x+y by 3 to get \frac{1}{3}x+\frac{1}{3}y.
M=\frac{1}{3}x+\frac{1}{3}y
Swap sides so that all variable terms are on the left hand side.
\frac{1}{3}x+\frac{1}{3}y=M
Divide each term of x+y by 3 to get \frac{1}{3}x+\frac{1}{3}y.
\frac{1}{3}x=M-\frac{1}{3}y
Subtract \frac{1}{3}y from both sides.
\frac{1}{3}x=-\frac{y}{3}+M
The equation is in standard form.
\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{-\frac{y}{3}+M}{\frac{1}{3}}
Multiply both sides by 3.
x=\frac{-\frac{y}{3}+M}{\frac{1}{3}}
Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.
x=3M-y
Divide M-\frac{y}{3} by \frac{1}{3} by multiplying M-\frac{y}{3} by the reciprocal of \frac{1}{3}.