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\frac{\left(x+7\right)\times 4}{3\left(5x+35\right)}
Divide \frac{x+7}{3} by \frac{5x+35}{4} by multiplying \frac{x+7}{3} by the reciprocal of \frac{5x+35}{4}.
\frac{4\left(x+7\right)}{3\times 5\left(x+7\right)}
Factor the expressions that are not already factored.
\frac{4}{3\times 5}
Cancel out x+7 in both numerator and denominator.
\frac{4}{15}
Multiply 3 and 5 to get 15.