Solve for x
x\in \left(-2,3\right)
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x+2>0 x-3<0
For the quotient to be negative, x+2 and x-3 have to be of the opposite signs. Consider the case when x+2 is positive and x-3 is negative.
x\in \left(-2,3\right)
The solution satisfying both inequalities is x\in \left(-2,3\right).
x-3>0 x+2<0
Consider the case when x-3 is positive and x+2 is negative.
x\in \emptyset
This is false for any x.
x\in \left(-2,3\right)
The final solution is the union of the obtained solutions.
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