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\left(x+10\right)\left(x+10\right)=x\left(x-5\right)
Variable x cannot be equal to any of the values -10,0 since division by zero is not defined. Multiply both sides of the equation by x\left(x+10\right), the least common multiple of x,x+10.
\left(x+10\right)^{2}=x\left(x-5\right)
Multiply x+10 and x+10 to get \left(x+10\right)^{2}.
x^{2}+20x+100=x\left(x-5\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+10\right)^{2}.
x^{2}+20x+100=x^{2}-5x
Use the distributive property to multiply x by x-5.
x^{2}+20x+100-x^{2}=-5x
Subtract x^{2} from both sides.
20x+100=-5x
Combine x^{2} and -x^{2} to get 0.
20x+100+5x=0
Add 5x to both sides.
25x+100=0
Combine 20x and 5x to get 25x.
25x=-100
Subtract 100 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-100}{25}
Divide both sides by 25.
x=-4
Divide -100 by 25 to get -4.