Solve for x
x=2
x=8
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\left(2x+32\right)\left(x+1\right)=3x\times 18
Variable x cannot be equal to any of the values -16,0 since division by zero is not defined. Multiply both sides of the equation by 6x\left(x+16\right), the least common multiple of 3x,2x+32.
2x^{2}+34x+32=3x\times 18
Use the distributive property to multiply 2x+32 by x+1 and combine like terms.
2x^{2}+34x+32=54x
Multiply 3 and 18 to get 54.
2x^{2}+34x+32-54x=0
Subtract 54x from both sides.
2x^{2}-20x+32=0
Combine 34x and -54x to get -20x.
x^{2}-10x+16=0
Divide both sides by 2.
a+b=-10 ab=1\times 16=16
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+16. To find a and b, set up a system to be solved.
-1,-16 -2,-8 -4,-4
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 16.
-1-16=-17 -2-8=-10 -4-4=-8
Calculate the sum for each pair.
a=-8 b=-2
The solution is the pair that gives sum -10.
\left(x^{2}-8x\right)+\left(-2x+16\right)
Rewrite x^{2}-10x+16 as \left(x^{2}-8x\right)+\left(-2x+16\right).
x\left(x-8\right)-2\left(x-8\right)
Factor out x in the first and -2 in the second group.
\left(x-8\right)\left(x-2\right)
Factor out common term x-8 by using distributive property.
x=8 x=2
To find equation solutions, solve x-8=0 and x-2=0.
\left(2x+32\right)\left(x+1\right)=3x\times 18
Variable x cannot be equal to any of the values -16,0 since division by zero is not defined. Multiply both sides of the equation by 6x\left(x+16\right), the least common multiple of 3x,2x+32.
2x^{2}+34x+32=3x\times 18
Use the distributive property to multiply 2x+32 by x+1 and combine like terms.
2x^{2}+34x+32=54x
Multiply 3 and 18 to get 54.
2x^{2}+34x+32-54x=0
Subtract 54x from both sides.
2x^{2}-20x+32=0
Combine 34x and -54x to get -20x.
x=\frac{-\left(-20\right)±\sqrt{\left(-20\right)^{2}-4\times 2\times 32}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, -20 for b, and 32 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-20\right)±\sqrt{400-4\times 2\times 32}}{2\times 2}
Square -20.
x=\frac{-\left(-20\right)±\sqrt{400-8\times 32}}{2\times 2}
Multiply -4 times 2.
x=\frac{-\left(-20\right)±\sqrt{400-256}}{2\times 2}
Multiply -8 times 32.
x=\frac{-\left(-20\right)±\sqrt{144}}{2\times 2}
Add 400 to -256.
x=\frac{-\left(-20\right)±12}{2\times 2}
Take the square root of 144.
x=\frac{20±12}{2\times 2}
The opposite of -20 is 20.
x=\frac{20±12}{4}
Multiply 2 times 2.
x=\frac{32}{4}
Now solve the equation x=\frac{20±12}{4} when ± is plus. Add 20 to 12.
x=8
Divide 32 by 4.
x=\frac{8}{4}
Now solve the equation x=\frac{20±12}{4} when ± is minus. Subtract 12 from 20.
x=2
Divide 8 by 4.
x=8 x=2
The equation is now solved.
\left(2x+32\right)\left(x+1\right)=3x\times 18
Variable x cannot be equal to any of the values -16,0 since division by zero is not defined. Multiply both sides of the equation by 6x\left(x+16\right), the least common multiple of 3x,2x+32.
2x^{2}+34x+32=3x\times 18
Use the distributive property to multiply 2x+32 by x+1 and combine like terms.
2x^{2}+34x+32=54x
Multiply 3 and 18 to get 54.
2x^{2}+34x+32-54x=0
Subtract 54x from both sides.
2x^{2}-20x+32=0
Combine 34x and -54x to get -20x.
2x^{2}-20x=-32
Subtract 32 from both sides. Anything subtracted from zero gives its negation.
\frac{2x^{2}-20x}{2}=-\frac{32}{2}
Divide both sides by 2.
x^{2}+\left(-\frac{20}{2}\right)x=-\frac{32}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}-10x=-\frac{32}{2}
Divide -20 by 2.
x^{2}-10x=-16
Divide -32 by 2.
x^{2}-10x+\left(-5\right)^{2}=-16+\left(-5\right)^{2}
Divide -10, the coefficient of the x term, by 2 to get -5. Then add the square of -5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-10x+25=-16+25
Square -5.
x^{2}-10x+25=9
Add -16 to 25.
\left(x-5\right)^{2}=9
Factor x^{2}-10x+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-5\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
x-5=3 x-5=-3
Simplify.
x=8 x=2
Add 5 to both sides of the equation.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}