Solve u^8/y^8=2019

$$\frac { u ^ { 8 } } { y ^ { 8 } } = 2019$$

Solve for u (complex solution)

$$u\in \sqrt{2}\sqrt[8]{2019}\left(\frac{1}{2}+\frac{1}{2}i\right)y,\sqrt[8]{2019}y,\sqrt[8]{2019}iy,\sqrt{2}\sqrt[8]{2019}\left(-\frac{1}{2}+\frac{1}{2}i\right)y,-\sqrt[8]{2019}y,\sqrt{2}\sqrt[8]{2019}\left(-\frac{1}{2}-\frac{1}{2}i\right)y,-\sqrt[8]{2019}iy,\sqrt{2}\sqrt[8]{2019}\left(\frac{1}{2}-\frac{1}{2}i\right)y$$

$$y\neq 0$$

Solve for y (complex solution)

$$y\in \sqrt{2}\times 2019^{\frac{7}{8}}\left(\frac{1}{4038}+\frac{1}{4038}i\right)u,\frac{2019^{\frac{7}{8}}u}{2019},\frac{2019^{\frac{7}{8}}iu}{2019},\sqrt{2}\times 2019^{\frac{7}{8}}\left(-\frac{1}{4038}+\frac{1}{4038}i\right)u,-\frac{2019^{\frac{7}{8}}u}{2019},\sqrt{2}\times 2019^{\frac{7}{8}}\left(-\frac{1}{4038}-\frac{1}{4038}i\right)u,-\frac{2019^{\frac{7}{8}}iu}{2019},\sqrt{2}\times 2019^{\frac{7}{8}}\left(\frac{1}{4038}-\frac{1}{4038}i\right)u$$

$$u\neq 0$$

Solve for u

$$u=\sqrt[8]{2019}y$$

$$u=-\sqrt[8]{2019}y\text{, }y\neq 0$$

Solve for y

$$y=\frac{2019^{\frac{7}{8}}u}{2019}$$

$$y=-\frac{2019^{\frac{7}{8}}u}{2019}\text{, }u\neq 0$$