Solve t+8/3=t

$$\frac { t + 8 } { 3 } = t$$

Solve for t

$$t=4$$

Steps for Solving Linear Equation

Divide each term of t+8 by 3 to get \frac{1}{3}t+\frac{8}{3}.

$$\frac{1}{3}t+\frac{8}{3}=t$$

Subtract t from both sides.

$$\frac{1}{3}t+\frac{8}{3}-t=0$$

Combine \frac{1}{3}t and -t to get -\frac{2}{3}t.

$$-\frac{2}{3}t+\frac{8}{3}=0$$

Subtract \frac{8}{3} from both sides. Anything subtracted from zero gives its negation.

$$-\frac{2}{3}t=-\frac{8}{3}$$

Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.

$$t=-\frac{8}{3}\left(-\frac{3}{2}\right)$$

Multiply -\frac{8}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$t=\frac{-8\left(-3\right)}{3\times 2}$$

Do the multiplications in the fraction \frac{-8\left(-3\right)}{3\times 2}.

$$t=\frac{24}{6}$$

Divide 24 by 6 to get 4.

$$t=4$$