\frac { k g } { 60 } | \frac { ? } { 36 }
Evaluate
\frac{gk}{2160}
Differentiate w.r.t. k
\frac{g}{2160}
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\frac{kg}{60}\times \frac{1}{36}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{1}{36} is \frac{1}{36}.
\frac{kg}{60\times 36}
Multiply \frac{kg}{60} times \frac{1}{36} by multiplying numerator times numerator and denominator times denominator.
\frac{kg}{2160}
Multiply 60 and 36 to get 2160.
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