Solve i^2+i^3+i^4/i=

$$\frac { i ^ { 2 } + i ^ { 3 } + i ^ { 4 } } { i } =$$

Evaluate

$$-1$$

Solution Steps

Calculate i to the power of 2 and get -1.

$$\frac{-1+i^{3}+i^{4}}{i}$$

Calculate i to the power of 3 and get -i.

$$\frac{-1-i+i^{4}}{i}$$

Calculate i to the power of 4 and get 1.

$$\frac{-1-i+1}{i}$$

Do the additions in -1-i+1.

$$\frac{-i}{i}$$

Divide -i by i to get -1.

$$-1$$

Real Part

$$-1$$

Solution Steps

Calculate i to the power of 2 and get -1.

$$Re(\frac{-1+i^{3}+i^{4}}{i})$$

Calculate i to the power of 3 and get -i.

$$Re(\frac{-1-i+i^{4}}{i})$$

Calculate i to the power of 4 and get 1.

$$Re(\frac{-1-i+1}{i})$$

Do the additions in -1-i+1.

$$Re(\frac{-i}{i})$$

Divide -i by i to get -1.

$$Re(-1)$$

The real part of -1 is -1.

$$-1$$