\frac { d ^ { 2 } T } { d s ^ { 2 } } + \frac { 1 } { r } \cdot \frac { d T } { d s } = 0
Solve for r
r\neq 0
Solve for T (complex solution)
T\in \mathrm{C}
r\neq 0
Solve for T
T\in \mathrm{R}
r\neq 0
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r\frac{\mathrm{d}(T)}{\mathrm{d}s^{2}}+1\frac{\mathrm{d}(T)}{\mathrm{d}s}=0
Variable r cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by r.
r\frac{\mathrm{d}(T)}{\mathrm{d}s^{2}}=-\frac{\mathrm{d}(T)}{\mathrm{d}s}
Subtract 1\frac{\mathrm{d}(T)}{\mathrm{d}s} from both sides. Anything subtracted from zero gives its negation.
\text{true}
The equation is in standard form.
r\in \mathrm{R}
This is true for any r.
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