Solve d^2/d-b+b^2/b-d

$$\frac { d ^ { 2 } } { d - b } + \frac { b ^ { 2 } } { b - d }$$

Evaluate

$$b+d$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of d-b and b-d is b-d. Multiply \frac{d^{2}}{d-b} times \frac{-1}{-1}.

$$\frac{-d^{2}}{b-d}+\frac{b^{2}}{b-d}$$

Since \frac{-d^{2}}{b-d} and \frac{b^{2}}{b-d} have the same denominator, add them by adding their numerators.

$$\frac{-d^{2}+b^{2}}{b-d}$$

Factor the expressions that are not already factored in \frac{-d^{2}+b^{2}}{b-d}.

$$\frac{\left(-b+d\right)\left(-b-d\right)}{b-d}$$

Extract the negative sign in d-b.

$$\frac{-\left(b-d\right)\left(-b-d\right)}{b-d}$$

Cancel out b-d in both numerator and denominator.

$$-\left(-b-d\right)$$

Expand the expression.

$$b+d$$

Differentiate w.r.t. d

$$1$$