Solve b-2a/2+1=3b

$$\frac { b - 2 a } { 2 } + 1 = 3 b$$

Solve for a

$$a=-\frac{5b}{2}+1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$b-2a+2=6b$$

Subtract b from both sides.

$$-2a+2=6b-b$$

Combine 6b and -b to get 5b.

$$-2a+2=5b$$

Subtract 2 from both sides.

$$-2a=5b-2$$

Divide both sides by -2.

$$\frac{-2a}{-2}=\frac{5b-2}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$a=\frac{5b-2}{-2}$$

Divide 5b-2 by -2.

$$a=-\frac{5b}{2}+1$$

Solve for b

$$b=\frac{2-2a}{5}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$b-2a+2=6b$$

Subtract 6b from both sides.

$$b-2a+2-6b=0$$

Combine b and -6b to get -5b.

$$-5b-2a+2=0$$

Add 2a to both sides. Anything plus zero gives itself.

$$-5b+2=2a$$

Subtract 2 from both sides.

$$-5b=2a-2$$

Divide both sides by -5.

$$\frac{-5b}{-5}=\frac{2a-2}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$b=\frac{2a-2}{-5}$$

Divide -2+2a by -5.

$$b=\frac{2-2a}{5}$$