Solve b^2/4a^2-c/a

$$\frac { b ^ { 2 } } { 4 a ^ { 2 } } - \frac { c } { a }$$

Evaluate

$$\frac{b^{2}-4ac}{4a^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4a^{2} and a is 4a^{2}. Multiply \frac{c}{a} times \frac{4a}{4a}.

$$\frac{b^{2}}{4a^{2}}-\frac{c\times 4a}{4a^{2}}$$

Since \frac{b^{2}}{4a^{2}} and \frac{c\times 4a}{4a^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{b^{2}-c\times 4a}{4a^{2}}$$

Do the multiplications in b^{2}-c\times 4a.

$$\frac{b^{2}-4ca}{4a^{2}}$$

Factor

$$\frac{b^{2}-4ac}{4a^{2}}$$