Solve for b
b=4
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3\left(b+2\right)+2\left(2b+1\right)=36
Multiply both sides of the equation by 6, the least common multiple of 2,3.
3b+6+2\left(2b+1\right)=36
Use the distributive property to multiply 3 by b+2.
3b+6+4b+2=36
Use the distributive property to multiply 2 by 2b+1.
7b+6+2=36
Combine 3b and 4b to get 7b.
7b+8=36
Add 6 and 2 to get 8.
7b=36-8
Subtract 8 from both sides.
7b=28
Subtract 8 from 36 to get 28.
b=\frac{28}{7}
Divide both sides by 7.
b=4
Divide 28 by 7 to get 4.
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