Solve for a (complex solution)
a\in \mathrm{C}\setminus 1,-1
Solve for a
a\in \mathrm{R}\setminus 1,-1
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\left(2a+2\right)\left(a-1\right)=\left(a-1\right)\left(2a+2\right)
Variable a cannot be equal to any of the values -1,1 since division by zero is not defined. Multiply both sides of the equation by 4\left(a-1\right)\left(a+1\right), the least common multiple of 2a-2,4+4a.
a\in \mathrm{C}
This is true for any a.
a\in \mathrm{C}\setminus -1,1
Variable a cannot be equal to any of the values -1,1.
\left(2a+2\right)\left(a-1\right)=\left(a-1\right)\left(2a+2\right)
Variable a cannot be equal to any of the values -1,1 since division by zero is not defined. Multiply both sides of the equation by 4\left(a-1\right)\left(a+1\right), the least common multiple of 2a-2,4+4a.
a\in \mathrm{R}
This is true for any a.
a\in \mathrm{R}\setminus -1,1
Variable a cannot be equal to any of the values -1,1.
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