Solve a+2/3=b-1

$$\frac { a + 2 } { 3 } = b - 1$$

Solve for a

$$a=3b-5$$

Solution Steps

Multiply both sides of the equation by 3.

$$a+2=3b-3$$

Subtract 2 from both sides.

$$a=3b-3-2$$

Subtract 2 from -3 to get -5.

$$a=3b-5$$

Solve for b

$$b=\frac{a+5}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$a+2=3b-3$$

Swap sides so that all variable terms are on the left hand side.

$$3b-3=a+2$$

Add 3 to both sides.

$$3b=a+2+3$$

Add 2 and 3 to get 5.

$$3b=a+5$$

Divide both sides by 3.

$$\frac{3b}{3}=\frac{a+5}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$b=\frac{a+5}{3}$$