Solve D/h=1+z/z

$$\frac { D } { h } = \frac { 1 + z } { z }$$

Solve for D

$$D=h+\frac{h}{z}$$

$$h\neq 0\text{ and }z\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by hz, the least common multiple of h,z.

$$zD=h\left(1+z\right)$$

Use the distributive property to multiply h by 1+z.

$$zD=h+hz$$

The equation is in standard form.

$$zD=hz+h$$

Divide both sides by z.

$$\frac{zD}{z}=\frac{hz+h}{z}$$

Dividing by z undoes the multiplication by z.

$$D=\frac{hz+h}{z}$$

Divide h+hz by z.

$$D=h+\frac{h}{z}$$

Solve for h

$$\left\{\begin{matrix}h=\frac{Dz}{z+1}\text{, }&z\neq 0\text{ and }D\neq 0\text{ and }z\neq -1\\h\neq 0\text{, }&D=0\text{ and }z=-1\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable h cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by hz, the least common multiple of h,z.

$$zD=h\left(1+z\right)$$

Use the distributive property to multiply h by 1+z.

$$zD=h+hz$$

Swap sides so that all variable terms are on the left hand side.

$$h+hz=zD$$

Combine all terms containing h.

$$\left(1+z\right)h=zD$$

The equation is in standard form.

$$\left(z+1\right)h=Dz$$

Divide both sides by z+1.

$$\frac{\left(z+1\right)h}{z+1}=\frac{Dz}{z+1}$$

Dividing by z+1 undoes the multiplication by z+1.

$$h=\frac{Dz}{z+1}$$

Variable h cannot be equal to 0.

$$h=\frac{Dz}{z+1}\text{, }h\neq 0$$