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\frac{9}{4}x-\frac{15}{4}=x
Divide each term of 9x-15 by 4 to get \frac{9}{4}x-\frac{15}{4}.
\frac{9}{4}x-\frac{15}{4}-x=0
Subtract x from both sides.
\frac{5}{4}x-\frac{15}{4}=0
Combine \frac{9}{4}x and -x to get \frac{5}{4}x.
\frac{5}{4}x=\frac{15}{4}
Add \frac{15}{4} to both sides. Anything plus zero gives itself.
x=\frac{15}{4}\times \frac{4}{5}
Multiply both sides by \frac{4}{5}, the reciprocal of \frac{5}{4}.
x=\frac{15\times 4}{4\times 5}
Multiply \frac{15}{4} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{15}{5}
Cancel out 4 in both numerator and denominator.
x=3
Divide 15 by 5 to get 3.